5z^2-8z+3=0

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Solution for 5z^2-8z+3=0 equation: 



5z^2-8z+3=0

a = 5; b = -8; c = +3;
Δ = b2-4ac
Δ = -82-4·5·3
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2}{2*5}=\frac{6}{10}
=3/5
$


$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2}{2*5}=\frac{10}{10}
=1
$

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